HINDE NA AKO NAKIKILOKO SA INYO AYUSIN NIYO OR REPORT
1. In a city, a monthly telephone bill consists of two parts: a fixed charge and a charge that varies directly as the number of calls made in month. if 60 calls are made, the bill is ₱1,100. if 300 calls made, the bill is ₱2,300.
a. express the bill ₱B in terms of the number N of calls are made
b. How much is bill needed when 180 calls are made?
2. the friction acting the car is partly constant and partly varies directly as the square of it's velocity. When the velocity is 10kpmh, the friction is 1050N. when the velocity is 20kpmh, the friction 1200N. find the friction when the velocity is 30kpmh
3. The cost of making a circular porcelain plate with a gold rim partly varies directly as a its radius and partly varies directly as a square of its radius. When the radius is 6cm, the cost is ₱324 when the radius is 10cm the cost is ₱700. Find
a. The cost of making a plate with radius 12 cm
b. the radius of a plate which cost ₱406
Need complete solution pls
1. In a city, a monthly telephone bill consists of two parts: a fixed charge and a charge that varies directly as the number of calls made in month. if 60 calls are made, the bill is ₱1,100. if 300 calls made, the bill is ₱2,300.
a. express the bill ₱B in terms of the number N of calls are made
b. How much is bill needed when 180 calls are made?
2. the friction acting the car is partly constant and partly varies directly as the square of it's velocity. When the velocity is 10kpmh, the friction is 1050N. when the velocity is 20kpmh, the friction 1200N. find the friction when the velocity is 30kpmh
3. The cost of making a circular porcelain plate with a gold rim partly varies directly as a its radius and partly varies directly as a square of its radius. When the radius is 6cm, the cost is ₱324 when the radius is 10cm the cost is ₱700. Find
a. The cost of making a plate with radius 12 cm
b. the radius of a plate which cost ₱406
Need complete solution pls
Add an Answer
More Questions From This User See All
Answers & Comments
Answer:
1.
a. Let x be the fixed charge and y be the charge per call. We can set up two equations using the given information:
60y + x = 1100
300y + x = 2300
Subtracting the first equation from the second, we get:
240y = 1200
y = 5
Substituting y = 5 into the first equation, we get:
60(5) + x = 1100
x = 800
Therefore, the bill B in terms of the number N of calls is:
B = 800 + 5N
b. When 180 calls are made, N = 180. Substituting this into the equation from part a, we get:
B = 800 + 5(180)
B = 1700
Therefore, the bill needed when 180 calls are made is ₱1700.
2. Let Fc be the constant friction and Fv be the friction that varies with velocity squared. We can set up two equations using the given information:
10^2Fc + 10^2Fv = 1050
20^2Fc + 20^2Fv = 1200
Simplifying these equations, we get:
100Fc + 100Fv = 1050
400Fc + 400Fv = 1200
Subtracting the first equation from the second, we get:
300Fc + 300Fv = 150
Dividing both sides by 300, we get:
Fc + Fv = 0.5
Substituting Fc = 0.5 - Fv into the first equation, we get:
100(0.5 - Fv) + 100Fv = 1050
50 - 100Fv + 100Fv = 1050
Fv = 10
Therefore, the friction when the velocity is 30kpmh is:
30^2(10) = 9000N
3.
a. Let Cr be the cost that varies directly with the radius and Cs be the cost that varies directly with the square of the radius. We can set up two equations using the given information:
6Cr + 6^2Cs = 324
10Cr + 10^2Cs = 700
Simplifying these equations, we get:
6Cr + 36Cs = 324
10Cr + 100Cs = 700
Multiplying the first equation by 25 and subtracting it from the second equation, we get:
2200Cs = 1900
Cs = 0.8636
Substituting Cs = 0.8636 into the first equation, we get:
6Cr + 6^2(0.8636) = 324
Cr = 43.6364
Therefore, the cost of making a plate with radius 12cm is:
12(43.6364) + 12^2(0.8636) = ₱628.30
b. Let r be the radius of the plate. We can set up an equation using the given information:
Cr + r^2Cs = 406
Substituting Cr = 43.6364 and Cs = 0.8636, we get:
43.6364r + 0.8636r^2 = 406
Solving for r using a quadratic formula, we get:
r = 9.222cm (rounded to three decimal places)
Therefore, the radius of a plate which cost ₱406 is approximately 9.222cm.
PAMARK NALANG PARA MATULONGAN RANGGO KO
Answer:
a. Let x be the fixed charge and y be the variable charge per call. We can write two equations based on the given information:
60y + x = 1100
300y + x = 2300
Subtracting the first equation from the second, we get:
240y = 1200
y = 5
Substituting y = 5 in the first equation, we get:
60(5) + x = 1100
x = 800
Therefore, the bill B in terms of the number of calls N is:
B = 800 + 5N
b. To find the bill when 180 calls are made, we substitute N = 180 in the equation we found in part a:
B = 800 + 5(180)
B = 1700
Therefore, the bill needed when 180 calls are made is ₱1700.
Let F be the total friction acting on the car, k be the constant friction coefficient, and v be the velocity of the car. We can write two equations based on the given information:
k + 100v^2 = 1050
k + 400v^2 = 1200
Subtracting the first equation from the second, we get:
300v^2 = 150
v^2 = 0.5
v = 0.707 kpmh (approx.)
Substituting v = 10 in the first equation, we get:
k + 100(10)^2 = 1050
k = 550
Therefore, the equation for the friction F is:
F = 550 + 100v^2
Substituting v = 30, we get:
F = 550 + 100(30)^2
F = 85550 N
Therefore, the friction when the velocity is 30 kpmh is 85550 N.
Let C be the total cost of making the plate, k be the constant of proportionality for the first part, and h be the constant of proportionality for the second part. We can write two equations based on the given information:
k(6) + h(6)^2 = 324
k(10) + h(10)^2 = 700
Simplifying the first equation, we get:
6k + 36h = 324
Dividing both sides by 6, we get:
k + 6h = 54
Simplifying the second equation, we get:
10k + 100h = 700
Dividing both sides by 10, we get:
k + 10h = 70
Subtracting the first equation from the second, we get:
4h = 16
h = 4
Substituting h = 4 in the first equation, we get:
k + 6(4) = 54
k = 30
Therefore, the equation for the cost C is:
C = 30r + 4r^2
a. To find the cost of making a plate with radius 12 cm, we substitute r = 12 in the equation we found:
C = 30(12) + 4(12)^2
C = 744
Therefore, the cost of making a plate with radius 12 cm is ₱744.
b. To find the radius of a plate which cost ₱406, we set the equation equal to 406 and solve for r:
30r + 4r^2 = 406
4r^2 + 30r - 406 = 0
Solving this quadratic equation,
Step-by-step explanation:
pa mark nalang