A particle of mass 10 grams is acted by a force of 150 dynes assuming that the particle starts from rest calculate the distance travelled in 10 seconds what is the velocity at the end of this period???
Answers & Comments
shubha1177
F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)] m=5 g (not necessary) t=3 s Impulse=? FORMULA; Impulse = F × t SOLUTION; Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)] m=5 g (not necessary) t=3 s Impulse=? FORMULA; Impulse = F × t SOLUTION; Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns mark me as a brainlist.....mate...
Answers & Comments
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)]
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
mark me as a brainlist.....mate...