Answer:
Given => AB parallel CD
So, Angle B +Angle C = 180° [co.int. angles]
Acc. to figure:-
[tex] \pink{ \tt{x+ y + z = 180 }}[/tex]
[tex] \frac{y}{2} + y + z = 180[/tex]
[tex] \frac{z}{4} + \frac{z}{2} + z = 180[/tex]
[tex] \underbrace{ \blue{ \frak{lcm}}}[/tex]
[tex] \frac{z + 2z + 4z}{4} = 180[/tex]
[tex] \frac{7}{4} z = 180[/tex]
[tex] \red{ \boxed{z = \frac{180 \times 4}{7} }}[/tex]
Now,
[tex] \orange{y = \frac{z}{2} = \frac{180 \times 4}{7 \times 2} = \frac{180 \times 2}{7} }[/tex]
[tex] \green{x = \frac{y}{2} = \frac{180 \times 2}{7 \times 2} = \frac{180}{7} }[/tex]
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Verified answer
Answer:
Given => AB parallel CD
So, Angle B +Angle C = 180° [co.int. angles]
Acc. to figure:-
[tex] \pink{ \tt{x+ y + z = 180 }}[/tex]
[tex] \frac{y}{2} + y + z = 180[/tex]
[tex] \frac{z}{4} + \frac{z}{2} + z = 180[/tex]
[tex] \underbrace{ \blue{ \frak{lcm}}}[/tex]
[tex] \frac{z + 2z + 4z}{4} = 180[/tex]
[tex] \frac{7}{4} z = 180[/tex]
[tex] \red{ \boxed{z = \frac{180 \times 4}{7} }}[/tex]
Now,
[tex] \orange{y = \frac{z}{2} = \frac{180 \times 4}{7 \times 2} = \frac{180 \times 2}{7} }[/tex]
[tex] \green{x = \frac{y}{2} = \frac{180 \times 2}{7 \times 2} = \frac{180}{7} }[/tex]
Plz mark me brainliest. (•_•)