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3. A triangular piece of lot has the following dimensions: 30 m, 95 m and 100 m. Determine the biggest angle formed by the three sides of the lot.
3. A triangular piece of lot has the following dimensions: 30 m, 95 m and 100 m. Determine the biggest angle formed by the three sides of the lot.
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Answer:
using law of cosine
Step-by-step explanation:
Assuming a= 30m,b=95m,c=100
find the angle of each A,B,C
*For C
c²=a²+b²-2ab cos C
100²=30²+95²-2(30)(95)cosC
10000=9925-5700 cosC
10000/-9925=9925/-9925 -5700cosC
75/-5700= -5700/-5700 cosC
-0.0132=cosC
C=cos^-1(-0.0132)
C=90.76°
For A
a/sin A=c/sinC
30/sinA=100/sin90.76
sinA=30sin90.76/100
sinA=0.299
A=sin^-1(0.299)
A=17.39°
For B
B=180-17.39-90.76
B=71.85°