Answer:

1). Xi=(4,0) , Yi=(0,−3)

A line passing through positive x intercept and negative y intercept will make acute angle with positive side of x axis. Hence slope is positive. As y intercept is 3 units from origin and x intercept is 4 units from origin, slope of line is 34. We already know y intercept so required equation is,

y=34x−3 ⟹

3x−4y−12=0

2). Sorry i dont know what the answer of number two is..

3). First Point: For

x

=

0

f

(

0

)

=

−

0

+

4

f

(

0

)

=

4

or

(

0

,

4

)

Second Point: For

x

=

4

f

(

4

)

=

−

4

+

4

f

(

4

)

=

0

or

(

4

,

0

)

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+x-4)(x^2+(y-4)^2-0.075)((x-4)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Explanation:

one way is to find the intercepts, that is where the graph

crosses the x and y axes

∙

let x = 0, in the equation for y-intercept

∙

let y = 0, in the equation for x-intercept

x

=

0

⇒

y

=

4

←

y-intercept

y

=

0

⇒

−

x

+

4

=

0

⇒

x

=

4

←

x-intercept

Plot the points

(

0

,

4

)

and

(

4

,

0

)

Draw a straight line through them for graph

graph{(y+x-4)((x-0)^2+(y-4)^2-0.04)((x-4)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

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