Let 'x' be the speed of the streamer in still water. Distance in both cases is same (Suppose it as d). We know, speed=distance/time. So when downstream, x + 2 = d/4 => d = 4x + 8. When upstream, x - 2 = d/5 => d = 5x - 10. Since, d is same =>4x + 8 = 5x - 10 => 5x - 4x = 10+8 => x = 18. Hence, speed of the streamer in still water is 18 kmph.
Answers & Comments
Let 'x' be the speed of the streamer in still water.
Distance in both cases is same (Suppose it as d). We know, speed=distance/time. So when downstream,
x + 2 = d/4
=> d = 4x + 8. When upstream,
x - 2 = d/5
=> d = 5x - 10. Since, d is same
=>4x + 8 = 5x - 10
=> 5x - 4x = 10+8
=> x = 18.
Hence, speed of the streamer in still water is 18 kmph.
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