Simple question
Draw the graph and analyse the given condition
Now take any integral value and try to make LHS and RHS limits eqaul
taking 1 we get
Lim(1+) =1=LHS
Lim(1-)=0=RHS
We are getting that LHS is not eqaul to RHS
this shows it will not continuous
similarly if we take any integral value we will always get LHS not equal to x
so,from this we can say
[x] will be continuous at all value of x except integers
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Answers & Comments
Simple question
Draw the graph and analyse the given condition
Now take any integral value and try to make LHS and RHS limits eqaul
taking 1 we get
Lim(1+) =1=LHS
Lim(1-)=0=RHS
We are getting that LHS is not eqaul to RHS
this shows it will not continuous
similarly if we take any integral value we will always get LHS not equal to x
so,from this we can say
[x] will be continuous at all value of x except integers