HEYA! 30 Points. don't spam or else ur account will be DELETED!! INSTRUCTION•The...

Questions

June 2021 2 20 Report

HEYA! 30 Points. don't spam or else ur account will be DELETED!!
INSTRUCTION
•The photo that I have given in attachment is from my text book and the given question which I have written is similar to the attached one but the numbers are different. so I want u to answer this question by the attachement answer method.
Rajesh wants to get an inverted image of height 7 cm of an
object kept at a distance of 25 cm. in front of a concave
mirror. The focal length of the mirror is 15 cm. At what
distance from the mirror should he place the screen? What
will be the type of image and what is the height of the object?

Edweena

Verified answer

$\huge\underline\mathrm\red{Given}$

hi = -7cm

u = -25cm

f = -15cm

v = ?

ho = ?

$\huge\underline\mathrm\red{Solution}$

Applying mirror Formula

$\implies\sf \frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\implies\sf \frac{1}{v}+\frac{-1}{25}=\frac{-1}{15}$

$\implies\sf \frac{1}{v}=\frac{1}{25}-\frac{1}{15}$

$\implies\sf \frac{1}{v}=\frac{3-5}{75}$

$\implies\sf \frac{1}{v}=\frac{-2}{75}$

$\implies\sf v=\frac{-75}{2}=-37.5cm$

Now height of object

$\implies\sf \frac{-v}{u}=\frac{hi}{ho}$

$\implies\sf \frac{-(-37.5)}{-25}=\frac{-7}{ho}$

$\implies\sf -1.5\times{ho}=-7$

$\implies\sf ho=\frac{-7}{-1.5}=+4.6cm$

Nature of image

Nature = real and inverted

Size = Diminished

Position = between centre of curvature and focus

Note :

v = image distance

u = object distance

hi = image height

ho = object height

f = focal length

ajayarathinam0404

Answer:

HEYA! 30 Points. don't spam or else ur account will be DELETED!!

INSTRUCTION

•The photo that I have given in attachment is from my text book and the given question which I have written is similar to the attached one but the numbers are different. so I want u to answer this question by the attachement answer method.

Rajesh wants to get an inverted image of height 7 cm of an

object kept at a distance of 25 cm. in front of a concave

mirror. The focal length of the mirror is 15 cm. At what

distance from the mirror should he place the screen? What

will be the type of image and what is the height of the objec

Add an Answer

Helpful Links

About Us

Terms and Conditions

Questions

Answers & Comments

Verified answer

Note :

Add an Answer

heya guysneed english tenses for all sentences refer to attachment20 pts

hey guys!please kindly go to mah recent question. its of english n all u have to...

solve this onedont spam or else your answers will be deletedrefer to att

hey guys20 ptssolve this by cramers rule

Hey night owls!i wanna know that why is 10 multiplied to 1000 kg ( refer to atta...

I need these answers now!!!!!question r of degree.aur spammers pls online test c...

please solve thisque write the names of parts shown and name of diagram

Hey guys!Tough question for uh all.20 pts n best will be marked as BRAINLIST!wha...

Hey night owls!30 pts. spamers uh account will be deleted if u spamhave a questi...

in triangle abc ab 63 cm ac 12 cm bc 6 cm find measure of angle a

Recommend Questions

Helpful Links

Helpful Social