Let the legth of rod be l , and mass be m
Mass of unit length = m/l
LINE 3:- picture 1
Take a small part dx whose distance from axis is x
Mass of that part =
Moment of interia of small part =m/l x².dx
Line 5: picure 2
Similary, as above
Mass of small part =
Distance from axis = xsinФ
limits = 0 to l
Line 4: Picture 3
limits = -l/2 to +l/2
Line 6:
No need of calculus.
Mass of rod = m
Distance from axis = x
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Verified answer
Let the legth of rod be l , and mass be m
Mass of unit length = m/l
LINE 3:- picture 1
Take a small part dx whose distance from axis is x
Mass of that part =![\frac{m}{l}dx \frac{m}{l}dx](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bl%7Ddx)
Moment of interia of small part =m/l x².dx
Line 5: picure 2
Similary, as above
Mass of small part =![\frac{m}{l}dx \frac{m}{l}dx](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bl%7Ddx)
Distance from axis = xsinФ
limits = 0 to l
Line 4: Picture 3
Mass of small part =![\frac{m}{l}dx \frac{m}{l}dx](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bl%7Ddx)
Distance from axis = xsinФ
limits = -l/2 to +l/2
Line 6:
No need of calculus.
Mass of rod = m
Distance from axis = x