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✍ QUESTION OF THE DAY ✍
➡ Three balls A,B and C are kept in a straight line. The separation between A and C is 1m,and B is placed at the midpoint between them.The masses of A,B and C are 100 g, 200 g and 300g respectively. Find the net gravitational force on (a) A ,(b) B and (c) C.
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✍ QUESTION OF THE DAY ✍
➡ Three balls A,B and C are kept in a straight line. The separation between A and C is 1m,and B is placed at the midpoint between them.The masses of A,B and C are 100 g, 200 g and 300g respectively. Find the net gravitational force on (a) A ,(b) B and (c) C.
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Answer:
A ------ 0.50 m -------- B -------- 0.50
-------- C
Ma = 0.100 kg
Mc = 0.300 kg
Mb = 0.200 kg
Net gravitational force Fa on A is
towards right side.
Fa= G Ma Mb/ 0.502 + G Ma Mc/
1.02
= 6.67 * 10-11 * 0.100
[ 0.200/ 0.502 + 0.300 /1] N
= 7.34 * 10-12 N.
Net gravitational force Fc on C is
towards B, left side and its
magnitude is equal to Fa ie., 7.34 * 10-12
Net gravitational force on B is Fb & is
towards C
Fb = G Mb [Mc- Ma 1/ 0.502
= 6.67 * 10-11 * 0.200 * 0.200 * 4 =
1.07 * 10-11N
4.0 (78)
0
208