Let the distance A and B be x km

Speed while going =60 km h-¹

∴ time required to go = x/60hr

Speed while returning =80 km h-¹

∴ time required to return = x/80hr

∴ total time required =( x/60 + x/80)hr =7x/240hr

And, total distance travelled =2x km

∴Average velocity

2x/7x/240

kmph=68.57km /h-¹

Answer:

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