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Rajusingh45
@Rajusingh45
June 2021
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Hey dears !!!!
Q.1) How many two digit numbers are divisible by 4 ?
Q.2) How many three digit numbers are divisible by 4 ?
✡✡ Full explanation Answers needed ✡✡✡
❌❎ No Spamm..❌❎
Answers & Comments
siddhartharao77
Verified answer
(1)
The first two digit number divisible by 4 = 12.
The last two digit number divisible by 4 = 96.
Let a be the first term and d be the common difference.
First term a = 12.
Last term an = 96
We know that an = a + (n - 1) * d
96 = 12 + (n - 1) * 4
84 = 4n - 4
88 = 4n
n = 22.
Therefore
there are 22 two-digit numbers divisible by 4.
(2)
The first 3-digit number divisible by 4 = 100
The last three digit number divisible by 4 = 996.
Let a be the first term and d be the common difference.
First term a = 100
Common difference d = 4
Last term an = 996
We know that an = a + (n - 1) * d
996 = 100 + (n - 1) * 4
896 = 4n - 4
900 = 4n
n = 900/4
n = 225.
Therefore there are 225 three digit numbers divisible by 4.
Hope this helps!
2 votes
Thanks 10
siddhartharao77
:-)
Rajusingh45
Edit 104 with 100
Rajusingh45
And thanks a lot sir ..
siddhartharao77
Mistake..Edited.. :-)
Rajusingh45
:)
siddhartharao77
Thanks uttu
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Answers & Comments
Verified answer
(1)The first two digit number divisible by 4 = 12.
The last two digit number divisible by 4 = 96.
Let a be the first term and d be the common difference.
First term a = 12.
Last term an = 96
We know that an = a + (n - 1) * d
96 = 12 + (n - 1) * 4
84 = 4n - 4
88 = 4n
n = 22.
Therefore there are 22 two-digit numbers divisible by 4.
(2)
The first 3-digit number divisible by 4 = 100
The last three digit number divisible by 4 = 996.
Let a be the first term and d be the common difference.
First term a = 100
Common difference d = 4
Last term an = 996
We know that an = a + (n - 1) * d
996 = 100 + (n - 1) * 4
896 = 4n - 4
900 = 4n
n = 900/4
n = 225.
Therefore there are 225 three digit numbers divisible by 4.
Hope this helps!