Answer:
Solution given:
∆ABC is a right angled triangle.
so it satisfy Pythagoras law
By using Pythagoras law
h²=p²+p²
c²=a²+b²
25²=a²+15²
a²=25²-15²
a=
value of a is 20.
now
Sin A=opposite/hypotenuse=20/25
A=Sin-¹(20/25)
<A=53.13°
again
Sin B=opposite/hypotenuse=15/25
B=Sin-¹(15/25)
<B=36.87°
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Answers & Comments
Answer:
Solution given:
∆ABC is a right angled triangle.
so it satisfy Pythagoras law
By using Pythagoras law
h²=p²+p²
c²=a²+b²
25²=a²+15²
a²=25²-15²
a=![\sqrt{400}=20 \sqrt{400}=20](https://tex.z-dn.net/?f=%5Csqrt%7B400%7D%3D20)
value of a is 20.
now
Sin A=opposite/hypotenuse=20/25
A=Sin-¹(20/25)
<A=53.13°
again
Sin B=opposite/hypotenuse=15/25
B=Sin-¹(15/25)
<B=36.87°