Answer:
1. 5
2. 9
3. Age of:
Jacky=7 yrs old
Stacy=14 yrs old
4. length=8 inches
width=4 inches
5. width = unit
length = 6 unit
Step-by-step explanation:
9 is the answer.
3. Let j be the age of Jacky
2j, the age of Stacy
Find j
Equation:
j(2j) = 98
Solution:
, the age of Jacky
age of Stacy = 2j
= 2(7)
= 14
4. Let w, the width
4+w, the length
w(4+w)= 96 squared inches, the area
Find w:
since length is a distance, the answers must be positive.
w=4 inches, the width
4+w=4+4=8 inches, the length
5. Let w, the width
3w-2, the length
w(3w-2)=16, the area
w(3w-2)=26
Since the answer must be positive, so the answer is
length= 3w-2
= 3()-2
= 8-2
length = 6
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Answers & Comments
Answer:
1. 5
2. 9
3. Age of:
Jacky=7 yrs old
Stacy=14 yrs old
4. length=8 inches
width=4 inches
5. width =
unit
length = 6 unit
Step-by-step explanation:
9 is the answer.
3. Let j be the age of Jacky
2j, the age of Stacy
Find j
Equation:
j(2j) = 98
Solution:
age of Stacy = 2j
= 2(7)
= 14
4. Let w, the width
4+w, the length
w(4+w)= 96 squared inches, the area
Find w:
Solution:
since length is a distance, the answers must be positive.
w=4 inches, the width
4+w=4+4=8 inches, the length
5. Let w, the width
3w-2, the length
w(3w-2)=16, the area
Find w:
w(3w-2)=26
Since the answer must be positive, so the answer is![\frac{8}{3} \frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
length= 3w-2
= 3(
)-2
= 8-2
length = 6