1. The energy of a photon is given by the equation E = hc/λ, where E is the energy of the photon, h is the Planck constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values given, we get:
E = (6.63 x 10^-34 J*s) * (2.998 x 10^8 m/s) / (3.2 x 10^-7 m)
E = 2.48 x 10^-19 J
So the energy of the atom that releases a photon with a wavelength of 3.2 x 10^-7 m is approximately 2.48 x 10^-19 J.
2. The energy required to photoelectrically eject an electron from a metal is equal to the energy of the incident photon minus the work function of the metal. The work function is the minimum energy required to remove an electron from the surface of the metal. In this case, the energy of the incident photon is 3.3 x 10^-20 J, so we can use the equation E = hc/λ to calculate the wavelength of the light needed to photoelectrically eject an electron from the metal:
E = hc/λ
3.3 x 10^-20 J = (6.63 x 10^-34 Js) * (2.998 x 10^8 m/s) / λ
λ = (6.63 x 10^-34 Js) * (2.998 x 10^8 m/s) / (3.3 x 10^-20 J)
λ = 2.01 x 10^-7 m
Thus, the wavelength of light that can photoelectrically eject an electron from this metal is approximately 2.01 x 10^-7 m.
Answers & Comments
Answer:
1. The energy of a photon is given by the equation E = hc/λ, where E is the energy of the photon, h is the Planck constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values given, we get:
E = (6.63 x 10^-34 J*s) * (2.998 x 10^8 m/s) / (3.2 x 10^-7 m)
E = 2.48 x 10^-19 J
So the energy of the atom that releases a photon with a wavelength of 3.2 x 10^-7 m is approximately 2.48 x 10^-19 J.
2. The energy required to photoelectrically eject an electron from a metal is equal to the energy of the incident photon minus the work function of the metal. The work function is the minimum energy required to remove an electron from the surface of the metal. In this case, the energy of the incident photon is 3.3 x 10^-20 J, so we can use the equation E = hc/λ to calculate the wavelength of the light needed to photoelectrically eject an electron from the metal:
E = hc/λ
3.3 x 10^-20 J = (6.63 x 10^-34 Js) * (2.998 x 10^8 m/s) / λ
λ = (6.63 x 10^-34 Js) * (2.998 x 10^8 m/s) / (3.3 x 10^-20 J)
λ = 2.01 x 10^-7 m
Thus, the wavelength of light that can photoelectrically eject an electron from this metal is approximately 2.01 x 10^-7 m.
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