Let's calculate the mass of the unknown part in each of the given reactions:
1. A sample of 30.5g of XY substance decomposes into substance X with 10.25g. To find the mass of substance Y, we can subtract the mass of X from the initial mass:
Initial mass (XY) - Mass of X = Mass of Y
30.5g - 10.25g = 20.25g
So, the mass of substance Y is 20.25 grams.
2. In the complete reaction of 22.99g of sodium (Na) with 35.45g of chlorine (Cl), we can use the balanced chemical equation for sodium chloride formation to find the mass of sodium chloride (NaCl) formed:
2Na + Cl2 -> 2NaCl
The molar mass of sodium (Na) is approximately 22.99 g/mol, and chlorine (Cl) is approximately 35.45 g/mol. From the equation, 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCl.
First, calculate the moles of Na and Cl2:
Moles of Na = 22.99g / 22.99 g/mol = 1 mole
Moles of Cl2 = 35.45g / 70.91 g/mol (molar mass of Cl2) = 0.5 moles
Since the ratio is 2:1 in the balanced equation, the moles of NaCl formed are also 1 mole. Now, calculate the mass of NaCl:
Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
Mass of NaCl = Moles of NaCl * Molar mass of NaCl
Mass of NaCl = 1 mole * 58.44 g/mol = 58.44g
So, 58.44 grams of sodium chloride (NaCl) are formed.
3. To find the grams of chlorine gas (Cl2) that reacted, you can use the information from the reaction. We know that 15.6g of sodium (Na) produced 39.7g of sodium chloride (NaCl). Using the balanced chemical equation:
2Na + Cl2 -> 2NaCl
We already calculated the moles of sodium (Na) in the previous question as 15.6g / 22.99 g/mol = 0.678 moles. Since the ratio is 2:1 in the balanced equation, this also represents the moles of Cl2 that reacted.
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Answer:
Let's calculate the mass of the unknown part in each of the given reactions:
1. A sample of 30.5g of XY substance decomposes into substance X with 10.25g. To find the mass of substance Y, we can subtract the mass of X from the initial mass:
Initial mass (XY) - Mass of X = Mass of Y
30.5g - 10.25g = 20.25g
So, the mass of substance Y is 20.25 grams.
2. In the complete reaction of 22.99g of sodium (Na) with 35.45g of chlorine (Cl), we can use the balanced chemical equation for sodium chloride formation to find the mass of sodium chloride (NaCl) formed:
2Na + Cl2 -> 2NaCl
The molar mass of sodium (Na) is approximately 22.99 g/mol, and chlorine (Cl) is approximately 35.45 g/mol. From the equation, 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCl.
First, calculate the moles of Na and Cl2:
Moles of Na = 22.99g / 22.99 g/mol = 1 mole
Moles of Cl2 = 35.45g / 70.91 g/mol (molar mass of Cl2) = 0.5 moles
Since the ratio is 2:1 in the balanced equation, the moles of NaCl formed are also 1 mole. Now, calculate the mass of NaCl:
Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl) = 58.44 g/mol
Mass of NaCl = Moles of NaCl * Molar mass of NaCl
Mass of NaCl = 1 mole * 58.44 g/mol = 58.44g
So, 58.44 grams of sodium chloride (NaCl) are formed.
3. To find the grams of chlorine gas (Cl2) that reacted, you can use the information from the reaction. We know that 15.6g of sodium (Na) produced 39.7g of sodium chloride (NaCl). Using the balanced chemical equation:
2Na + Cl2 -> 2NaCl
We already calculated the moles of sodium (Na) in the previous question as 15.6g / 22.99 g/mol = 0.678 moles. Since the ratio is 2:1 in the balanced equation, this also represents the moles of Cl2 that reacted.
Now, calculate the molar mass of Cl2:
Molar mass of Cl2 = 2 * 35.45 g/mol = 70.91 g/mol
Calculate the mass of Cl2:
Mass of Cl2 = Moles of Cl2 * Molar mass of Cl2
Mass of Cl2 = 0.678 moles * 70.91 g/mol = 48.23g
So, 48.23 grams of chlorine gas (Cl2) reacted.