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Synaya
@Synaya
July 2021
1
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Help me URGENT.....
I want both the questions to be done if you guys give only the answer of 1 or 2 question then I will report
I have increased the points
Answers & Comments
razy7292pblvn2
Area (∆ ABD) = 2ar (∆ADC).
and 2nd question
In ||gm ABCD ,
ar(△APC) = ar(△BCP) ---i)
[∵ triangles on the same base and between the same parallels have equal area]
Similarly, ar(△ADQ) = ar(△ADC) ---ii)
Now, ar(△ADQ) - ar(△ADP) = ar(△ADC) - ar(△ADP)
ar(△DPQ) = ar(△ACP) ---iii)
From (i) and (iii) , we have
ar(△BCP) = ar(△DPQ)
or ar(△BPC) = ar(△DPQ)
<marque>hope u got it
0 votes
Thanks 1
razy7292pblvn2
hope you got it❣️
razy7292pblvn2
thanks and mark brainliest please
Synaya
tysm
Synaya
let someone ans then i will mark u brainiest
razy7292pblvn2
thanks
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Answers & Comments
and 2nd question
In ||gm ABCD ,
ar(△APC) = ar(△BCP) ---i)
[∵ triangles on the same base and between the same parallels have equal area]
Similarly, ar(△ADQ) = ar(△ADC) ---ii)
Now, ar(△ADQ) - ar(△ADP) = ar(△ADC) - ar(△ADP)
ar(△DPQ) = ar(△ACP) ---iii)
From (i) and (iii) , we have
ar(△BCP) = ar(△DPQ)
or ar(△BPC) = ar(△DPQ)
<marque>hope u got it