aarzoo5
AD=CB(opposite sides of rect. are equal and parallel) take x and y on angle DAN and BCM respectively. In triangleDAN and BMC:- AD=BC(opp. sides of a rect.) DNA=BMC(each 90°) X=Y(alternate angles) so,triangle DAN congruent to triangle BCM(by AAS) BM = DN(C.P.C.T)
Answers & Comments
take x and y on angle DAN and BCM respectively.
In triangleDAN and BMC:-
AD=BC(opp. sides of a rect.)
DNA=BMC(each 90°)
X=Y(alternate angles)
so,triangle DAN congruent to triangle BCM(by AAS)
BM = DN(C.P.C.T)