11.) 2 ( ½ πr² ) + s²
= 2 { ½ × [ 3.14 × ( 6 / 2 ) ] } + 6²
= 2 [ ½ × ( 3.14 × 3 ) ] + 36
= 2 ( ½ × 9.42 ) + 36
= 2 × 4.71 + 36
= 9.42 + 36
= 45.42 m²
12.) 2 ( ½ πr² ) + ½ πr²
= 2 { ½ [ 3.14 × ( 2 / 2 )² ] } + { ½ [ 3.14 × ( 2² ) ] }
= 2 [ ½ ( 3.14 × 1 ) ] + [ ½ ( 3.14 × 4 ) ]
= 2 ( ½ × 3.14 ) + ½ × 12.56
= 2 × 1.57 + 6.28
= 3.14 + 6.28
= 9.42 cm ²
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Answers & Comments
Solution & Answer
11.) 2 ( ½ πr² ) + s²
= 2 { ½ × [ 3.14 × ( 6 / 2 ) ] } + 6²
= 2 [ ½ × ( 3.14 × 3 ) ] + 36
= 2 ( ½ × 9.42 ) + 36
= 2 × 4.71 + 36
= 9.42 + 36
= 45.42 m²
12.) 2 ( ½ πr² ) + ½ πr²
= 2 { ½ [ 3.14 × ( 2 / 2 )² ] } + { ½ [ 3.14 × ( 2² ) ] }
= 2 [ ½ ( 3.14 × 1 ) ] + [ ½ ( 3.14 × 4 ) ]
= 2 ( ½ × 3.14 ) + ½ × 12.56
= 2 × 1.57 + 6.28
= 3.14 + 6.28
= 9.42 cm ²