this is the same for numbers 1-5, number 7-9, but they're not all addition. read the questions carefully and think if they are pertaining to subtraction, division or multiplication.
6. for this number, just place the fraction of three-sevenths beside h.
this is the same for numbers 1-5, number 7-9, but they're not all addition. read the questions carefully and think if they are pertaining to subtraction, division or multiplication.
6. for this number, just place the fraction of three-sevenths beside h.
Answers & Comments
Answer:
ANSWER:
EVALUATE
1. 16 - x at x = 5
16 - 5 = 11
2. 3n at n = 11
3(11)
33
3. p³ at p = 2
2³
8
4. r + 4 at r = 13
13 + 4
17
5. 4/m + 1 at m = 1
4/1 + 1
4 + 1
5
answer the rest yourself. you must understand the lesson.
to do this activity, just substitute. as seen from my answers, the amount equal to the letter is substituted and used to solve the equation.
(here's an example:
9k + 4 at k = 2
k is equal to 2
substitute 2 to k beside 9
9(2)(multiply the two) - 1
18 - 1
17)
-------------------------------------------------------------------------
TRANSLATE
1. x + 2
(sum is the answer in addition)
this is the same for numbers 1-5, number 7-9, but they're not all addition. read the questions carefully and think if they are pertaining to subtraction, division or multiplication.
6. for this number, just place the fraction of three-sevenths beside h.
10. the answer is k/2.
-------------------------------------------------------------------------
AREA AND PERIMETER
use the formula. substitute.
formula for perimeter (rectangle) = 2(w+l)
formula for area (rectangle) = L(W) // L x W
(example, will be using number 1.)
1. PERIMETER = 2(5 + 7) = 2(12) = 24
AREA = 7(5) = 35
-------------------------------------------------------------------------
for the last one, you have to analyse the questions yourself.
if you need help understanding them then reply to me.
(not me copying the other kid :P)
Step-by-step explanation:
Area = 7(5) = 35
ANSWER:
EVALUATE
1. 16 - x at x = 5
16 - 5 = 11
2. 3n at n = 11
3(11)
33
3. p³ at p = 2
2³
8
4. r + 4 at r = 13
13 + 4
17
5. 4/m + 1 at m = 1
4/1 + 1
4 + 1
5
answer the rest yourself. you must understand the lesson.
to do this activity, just substitute. as seen from my answers, the amount equal to the letter is substituted and used to solve the equation.
(here's an example:
9k + 4 at k = 2
k is equal to 2
substitute 2 to k beside 9
9(2)(multiply the two) - 1
18 - 1
17)
-------------------------------------------------------------------------
TRANSLATE
1. x + 2
(sum is the answer in addition)
this is the same for numbers 1-5, number 7-9, but they're not all addition. read the questions carefully and think if they are pertaining to subtraction, division or multiplication.
6. for this number, just place the fraction of three-sevenths beside h.
10. the answer is k/2.
-------------------------------------------------------------------------
AREA AND PERIMETER
use the formula. substitute.
formula for perimeter (rectangle) = 2(w+l)
formula for area (rectangle) = L(W) // L x W
(example, will be using number 1.)
1. PERIMETER = 2(5 + 7) = 2(12) = 24
AREA = 7(5) = 35
-------------------------------------------------------------------------
for the last one, you have to analyse the questions yourself.
if you need help understanding them then reply to me.
hope i helped.
good luck.