[tex]\large\color{red}\boxed{\colorbox{white}{A}}\large\color{orange}\boxed{\colorbox{white}{N}}\large\color{blue}\boxed{\colorbox{white}{S}}\large\color{green}\boxed{\colorbox{white}{W}}\large\color{purple}\boxed{\colorbox{white}{E}}\large\color{gold}\boxed{\colorbox{white}{R}}[/tex]
[tex]\small\red{{ ━┈─────────────────────┈━ }}[/tex]
Q1
Q2
Q3
(a)
→P(6) = No. of 6's/total number
(b)
→P(negative) = No. of negative number/total number
→P(negative) =0/6
(c)
→P(odd) = No. of odd number/total number
→P(odd) = 3/6
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Answers & Comments
[tex]\large\color{red}\boxed{\colorbox{white}{A}}\large\color{orange}\boxed{\colorbox{white}{N}}\large\color{blue}\boxed{\colorbox{white}{S}}\large\color{green}\boxed{\colorbox{white}{W}}\large\color{purple}\boxed{\colorbox{white}{E}}\large\color{gold}\boxed{\colorbox{white}{R}}[/tex]
[tex]\small\red{{ ━┈─────────────────────┈━ }}[/tex]
Q1
→ S={1,2,3,4,5,6}
Q2
→ No. possible outcomes = 6
Q3
(a)
→P(6) = No. of 6's/total number
→P(6) = 1/6
(b)
→P(negative) = No. of negative number/total number
→P(negative) =0/6
→P(negative) = 0
(c)
→P(odd) = No. of odd number/total number
→P(odd) = 3/6
→P(odd) = 12
[tex]\small\red{{ ━┈─────────────────────┈━ }}[/tex]
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