hello guys so ayun repost ko po ito ulit pa answeran naman po ng maayos kung di nyo po kaya sagutan wag nalang po kayo mag react wala rin naman po kayon matutulong e pero sa mga makakaanswer thankyou po sana maansweran nyo po yun lang
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1. f(x) = x² + 2x
a = 1
b = 2
c = 0
f(x) = a(x - h)² + k
f(x) = 1[x - (-1)]² + (-1)
f(x) = (x + 1)² - 1
2. f(x) = x² + 6x + 9
a = 1
b = 6
c = 9
f(x) = a(x - h)² + k
f(x) = 1[x - (-3)]² + 0
f(x) = (x + 3)²
3. f(x) = -3x² + 6x - 5
a = -3
b = 6
c = -5
f(x) = a(x - h)² + k
f(x) = -3[x - (1)]² + (-2)
f(x) = -3(x - 1)² - 2
4. f(x) = 2x² + 4x - 8
a = 2
b = 4
c = -8
f(x) = a(x - h)² + k
f(x) = 2[x - (-1)]² + (-10)
f(x) = 2(x + 1)² - 10
5. f(x) = 6x² + 24x +25
a = 6
b = 24
c = 25
f(x) = a(x - h)² + k
f(x) = 6[x - (-2)]² + (1)
f(x) = 6(x + 2)² + 1
Answer:
download ka (p h o t o m a t h). doon yan masasagot. may step by step pa kung kailangan ng solution. sana makatulong.