Half of a herd of deer are grazing in the field and three fourth of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd.
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let the total no be x.
no. if deer grazing = 1/2 x
no. of deer playing = 3/4( x- x/2)
= 3/4 ( 2x-x /2)
= 3/4 × x/2
= 3x/8
no . of deer drinking water = 9.
a/q, x= x/2 +3x/8+ 9
x- x/2 - 3x /8 = 9
(8x - 4x - 3x )/8= 9
x/ 8 = 9
x= 9×8
x= 72.
hope it helps..
let total no. of deer = x
Number of deer grazing = 1/2 of x = 1/2x
therefore, Remaining deer = x-1/2x = 1/2x
Number of deer playing = 3/4 of 1/2x
= 3/8x
Number of deer drinking water = 9
Therefore, total deer in the herd = 1/2x + 3/8x + 9
x = 1/2x + 3/8x + 9
=>9 = X - (1/2x + 3/8x)
=> 9 = X- 7/8x
=> 9 = 1/8X
therefore, X (that is the total deer in the herd) = 9 x 8/1
= 72/1
= 72 deer in herd