Answer:
We have to find the marks Ajita scored in the test.
Let the actual marks be x
Total marks = 30
Given, 9(x + 10) = x²
9x + 90 = x²
x² - 9x - 90 = 0
On factoring,
x² - 15x + 6x - 90 = 0
x(x - 15) + 6(x - 15) = 0
(x + 6)(x - 15) = 0
Now, x + 6 = 0
x = -6
Also, x - 15 = 0
x = 15
Negative term x = -6 is neglected.
So, x = 15
Therefore, Ajita scored 15 marks in the examination.
Step-by-step explanation:
hope it is correct
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Verified answer
Answer:
We have to find the marks Ajita scored in the test.
Let the actual marks be x
Total marks = 30
Given, 9(x + 10) = x²
9x + 90 = x²
x² - 9x - 90 = 0
On factoring,
x² - 15x + 6x - 90 = 0
x(x - 15) + 6(x - 15) = 0
(x + 6)(x - 15) = 0
Now, x + 6 = 0
x = -6
Also, x - 15 = 0
x = 15
Negative term x = -6 is neglected.
So, x = 15
Therefore, Ajita scored 15 marks in the examination.
Step-by-step explanation:
hope it is correct