swati can row her boat at a speed of 5km /h in still water . if it takes her 1hour more to row the boat 5.25km upstream then to returnes downstream .find the speed of the stream
Answers & Comments
Xosmos
Let the speed of stream be "x" km/h Now speed down stream = 5 + x km/h And speed up stream = 5 - x km/h ( as speed of boat > speed of stream ) Now as time = distance / speed By substituting we get, :-
5.25/5+x - 5.25/5-x = 1 By solving the equation , we get
4x^2 + 42x - 100 = 0 By solving this by +50x and - 8x we get ,
(2x-4)(2x + 25) = 0 Hence x = -25/2 or 2 As speed cant be in negative Speed of stream = 2 km/ hr
Answers & Comments
Now speed down stream = 5 + x km/h
And speed up stream = 5 - x km/h ( as speed of boat > speed of stream )
Now as time = distance / speed
By substituting we get, :-
5.25/5+x - 5.25/5-x = 1
By solving the equation , we get
4x^2 + 42x - 100 = 0
By solving this by +50x and - 8x
we get ,
(2x-4)(2x + 25) = 0
Hence x = -25/2 or 2
As speed cant be in negative
Speed of stream = 2 km/ hr
HOPE IT HELPS YOU.
ALL THE BEST.
the Speed of the boat upstream = (5 - x) km/hr.
the Speed of the boat downstream = (5 + x)km/hr.
Given that It takes 1 hour more to row the boat 5.25km upstream than to return downstream.
5.25/(5 - x) = 5.25/(5 + x) + 1
525/(5 - x) = 525/(5 + x) + 100
525(5 + x) = 525(5 - x) + 100(5 + x)(5 - x)
525x + 2625 = 2625 - 525x + 100(25 - x^2)
525x + 2625 = 2625 - 525x + 2500 - 100x^2
100x^2 + 1050x - 2500 = 0
50(2x^2 + 21x - 50) = 0
2x^2 + 21x - 50
2x^2 - 4x + 25x - 50
2x(x - 2) + 25(x - 2) = 0
(x - 2) = 0 (or) 2x + 25 = 0
x = 2 (or) x = -25/2.
Therefore the speed of the stream = 2km/hr.
Hope this helps!