h, how far it cango after running for about 6 hours?...

Questions

September 2022 1 4 Report

C. PROBLEM SOLVING. Read the paragraph
carefully and compute for the SPEED.
1. Find speed when, distance is 142 km
and time is 2 hours.
2. A cyclist covers 950 m in 5 minutes.
Find his speed in km/hour.
3. The car moves 9 km/h, how far it can
go after running for about 6 hours?

Answers & Comments

TheoD

Verified answer

1. Find speed when, distance is 142 km and time is 2 hours.

Given :

distance = 142km
time = 2 hours
speed = ?

Solution :

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{142}{2} \\ \\ \boxed{\sf speed = 71\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

2. A cyclist covers 950 m in 5 minutes. Find his speed in km/hour.

Given :

distance = 950
time = 5 minutes
speed = ?

Solution :

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{0.95}{5} \\ \\ \sf speed = 0.19\: km/h \\ \\ \sf speed = 0.19 × 60 \\ \\ \boxed{\sf speed = 11.4\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

3. The car moves 9 km/h, how far it can go after running for about 6 hours?

Given :

distance = 9 km/h
time = 6 hours
speed = ?

Solution :

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{9}{6} \\ \\ \boxed{\sf speed = 1.5\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$