A driver leaves a city at 6 a.m. and another driver leaves the city from the same place w
11:30 a.m. in the same direction. If the average speed of the first driver was 55 kmh and the
driver was 62 km/h, find the time at which they will be together
11:30 a.m. in the same direction. If the average speed of the first driver was 55 kmh and the
driver was 62 km/h, find the time at which they will be together
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Answer:
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Step-by-step explanation:
Lets assume, they will be together in 't' hours after 6 a.m. when the first driver leaves the city.
As the second driver leaves at 11:30 a.m., that means he leaves (11:30am - 6am)= 5.5 hours after the first driver. So, the time duration for second driver is (t- 5.5) hours.
The average speed of the first driver was 55 km/hour and the second driver 65 km/hour.
As Distance= Speed × Time , so the equation will be ....
So, they will be together after 35.75 hours or 35 hours 45 minutes from 6 am , which is at (6 am+ 35 hours 45 minutes)= 5:45 p.m. on the next day.