Answer:
Sb = 40 kph
Sc = 100 kph
Step-by-step explanation:
Let Sc speed of the car
Let Sb speed of the bike
The formula for speed is
s =d/t
Solving for t
A car travels 50 km at the same time, a bike travels 20 km
Time of the car is equal to the time of the bike.
Tcar = Tbike
If the car's speed is 60 km/h faster than the bike,
Sc = Sb + 60
Substituting the values of to
Therefore the speed of the bike is 40 kph
Finding the speed of the car by substituting the speed of the bike to Sc = Sb + 60
Sc = 40 + 60
The speed of the car therefore is 100 kph
Checking:
t = d/s
The time of the car to travel 50 km with a speed of 100 kph
t = 50/100 = 0.5 hours
The time of the bike to travel 20 km with a speed of 40 kph
t = 20/40 = 0.5 hours
#CarryOnLearning
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Verified answer
Answer:
Sb = 40 kph
Sc = 100 kph
Step-by-step explanation:
Let Sc speed of the car
Let Sb speed of the bike
The formula for speed is
s =d/t
Solving for t
A car travels 50 km at the same time, a bike travels 20 km
Time of the car is equal to the time of the bike.
Tcar = Tbike
If the car's speed is 60 km/h faster than the bike,
Sc = Sb + 60
Substituting the values of
to ![\frac{d_{car} }{S_{c} } = \frac{d_{bike} }{S_{b} } \frac{d_{car} }{S_{c} } = \frac{d_{bike} }{S_{b} }](https://tex.z-dn.net/?f=%5Cfrac%7Bd_%7Bcar%7D%20%7D%7BS_%7Bc%7D%20%7D%20%20%3D%20%5Cfrac%7Bd_%7Bbike%7D%20%7D%7BS_%7Bb%7D%20%7D)
Therefore the speed of the bike is 40 kph
Finding the speed of the car by substituting the speed of the bike to Sc = Sb + 60
Sc = 40 + 60
Sc = 100 kph
The speed of the car therefore is 100 kph
Checking:
t = d/s
The time of the car to travel 50 km with a speed of 100 kph
t = 50/100 = 0.5 hours
The time of the bike to travel 20 km with a speed of 40 kph
t = 20/40 = 0.5 hours
#CarryOnLearning