On a two-lane road, car A is traveling with a speed of 36 km/h . Two cars B and C approach car A in opposite directions with a speed of 54 km/h each. At a certain instant, when the distance AB is equal to AC, both being 1 km, B decides to overtake A before C does. What minimum acceleration of car B is required to avoid an accident? Irrelevant Answers will be reported
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Let the car A move rightward.
Speed of car A,
Let the car B move rightward and car C move leftward, towards the car A, however.
Speed of car B,
Speed of car C,
Speed of each car with respect to car A will be,
Relative to A, time taken by car C to reach car A is,
During this time the car B should overtake A by travelling 1 km.
Let minimum acceleration of car B be
in ![\sf{km\,h^{-1}.} \sf{km\,h^{-1}.}](https://tex.z-dn.net/?f=%5Csf%7Bkm%5C%2Ch%5E%7B-1%7D.%7D)
By second equation of motion, the distance 1 km to reach A is given as,