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itzadi040
@itzadi040
May 2021
1
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16. Find limt
sin (a +3h)-3 sin(a+2h)+3 sin (a+h)-sin a/h cube
Answers & Comments
yoursolver50
What is the value of lim [sin (a+3h)-3sin (a+2h) +3sin(a+h)-sina] /h raised to 3 as h tends to 0?
Let x=
limh→0sin(a+3h)−3sin(a+2h)+3sin(a+h)−sinah3
In the numerator,
sin(a+3h)−sina=2⋅sin(a+3h−a2)⋅cos(a+3h+a2)
=2sin(3h2)cos(2a+3h2)
And,
−3sin(a+2h)+3sin(a+h)=3⋅2⋅sin(a+h−a−2h2)⋅cos(a+2h+a+h2)
=−6sin(h2)cos(2a+3h2)
Therefore, the numerator becomes
2sin(3h2)cos(2a+3h2)−6sin(h2)cos(2a+3h2)
=2cos(2a+3h2)[sin(3h2)−3sin(h2)]
Now, using triple angle identity for sin(3h2) ,
=2cos(2a+3h2)[3sin(h2)−4sin3(h2)−3sin(h2)]
=−8cos(2a+3h2)sin3(h2)
Therefore,
x=limh→0−8cos(2a+3h2)⋅[sin(h2)h2]3⋅18
Applying limits by using:
limθ→0sinθθ=1
We get,
x=−cos(2a+3⋅02)
x=−cosa
Hence,
limh→0sin(a+3h)−3sin(a+2h)+3sin(a+h)−sinah3
=−cosa
Hope that helps :)
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Answers & Comments
What is the value of lim [sin (a+3h)-3sin (a+2h) +3sin(a+h)-sina] /h raised to 3 as h tends to 0?
Let x=
limh→0sin(a+3h)−3sin(a+2h)+3sin(a+h)−sinah3
In the numerator,
sin(a+3h)−sina=2⋅sin(a+3h−a2)⋅cos(a+3h+a2)
=2sin(3h2)cos(2a+3h2)
And,
−3sin(a+2h)+3sin(a+h)=3⋅2⋅sin(a+h−a−2h2)⋅cos(a+2h+a+h2)
=−6sin(h2)cos(2a+3h2)
Therefore, the numerator becomes
2sin(3h2)cos(2a+3h2)−6sin(h2)cos(2a+3h2)
=2cos(2a+3h2)[sin(3h2)−3sin(h2)]
Now, using triple angle identity for sin(3h2) ,
=2cos(2a+3h2)[3sin(h2)−4sin3(h2)−3sin(h2)]
=−8cos(2a+3h2)sin3(h2)
Therefore,
x=limh→0−8cos(2a+3h2)⋅[sin(h2)h2]3⋅18
Applying limits by using:
limθ→0sinθθ=1
We get,
x=−cos(2a+3⋅02)
x=−cosa
Hence,
limh→0sin(a+3h)−3sin(a+2h)+3sin(a+h)−sinah3
=−cosa
Hope that helps :)