Methanamine (b) is formed as the product in the given reaction.

In the following reaction:

CH₃Br →→→→→→→ A →→→→→→→→→ B

           (AgNO₃)        (Sn/HCl)

In the first step of reaction

CH₃Br →→→→→→→ A  , A will be R-CN

               (AgNO₃)  

Alkyl halide in the presence of AgNO₃, follows SN¹ mechanism and form alkyl nitrate.

CH₃Br →→→→→→→ CH₃NO₃ + AgBr

             (AgNO₃)  

Now,

CH₃NO₃ →→→→→→→→→ B, B will be primary amine.

                 (Sn/HCl)

Sn and HCl are reducing agent, they will reduce:

NO₃ → NH₂

∴  CH₃NO₃ →→→→→→→→→ CH₃NH₂

                       (Sn/HCl)

Hence, Methanamine is formed as the product in the given reaction.

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