4. Solve. A car moving with a velocity of 55 km/h accelerates uniformly at the rate of 2 m/s^2. Calculate
A. the distance traveled from the place where the acceleration had begun to that where the velocity is 72 km/h
B. the time taken to cover this distance
A. the distance traveled from the place where the acceleration had begun to that where the velocity is 72 km/h
B. the time taken to cover this distance
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Answer:
41.63 meters
Explanation:
Given:
Initial velocity (Vo) = 55 km/hr
Final velocity (Vf) = 72 km/hr
Acceleration = 2 m/s2
Initial distance (Xo) = 0
Find time
Acceleration = Vf - Vo / time
Time = Vf - Vo / Acceleration
Time = (20 - 15.28) m/s / 2 m/s2
Time = 2.36 seconds
Answer:
41.63 meters
Step-by-step explanation:
Given:
Initial velocity (Vo) = 55 km/hr
Final velocity (Vf) = 72 km/hr
Acceleration = 2 m/s2
Initial distance (Xo) = 0
Explanation:
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