5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM What is the distance moved by the car if at 08:50 AM the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time Express the speed in km/h also
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Solution:
Solution:The initial reading of the odometer of the car =57321.0 km
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 km
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 km
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/min
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/min
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)= (15 x 3) km/ (1h)
Solution:The initial reading of the odometer of the car =57321.0 kmThe final reading of the odometer of the car = 57336.0 kmThe car starts at 8:30 AM and stops at 8:50 AM.Distance covered by car = (57336 - 57321) km = 15 kmTime taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hourSo Speed in km/minSpeed = (Distance travelled)/ (Time)= (15km)/ (20min)= 0.75km/minSpeed in km/h Speed = (Distance travelled)/ (Time)= (15km)/ (1/3h)= (15 x 3) km/ (1h)= 45km/h
Step-by-step explanation:
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Solution:
The initial reading of the odometer of the car =57321.0 km
The final reading of the odometer of the car = 57336.0 km
The car starts at 8:30 AM and stops at 8:50 AM.
Distance covered by car = (57336 - 57321) km = 15 km
Time taken between 08:30 AM to 08:50 AM = 20 minutes = 20/60 hour = 1/3 hour
So Speed in km/min
Speed = (Distance travelled)/ (Time)
= (15km)/ (20min)
= 0.75km/min
Speed in km/h Speed = (Distance travelled)/ (Time)
= (15km)/ (1/3h)
= (15 x 3) km/ (1h)
= 45km/h
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