☆ONLY FOR MODERATORS OR MATHS GENIUS☆[tex]find \: the \: sum \: of \: first \: 20 \: terms \: of \: \\ the \: series \\ 2 + 13 + 28 + 47 + 70.......[/tex]●●●●●●●●●●●●●●●●●●●●●♡SOLUTION MUST♡NO SPAMMING♡CONTENT QUALITY REQUIRED▪▪▪▪▪▪▪▪▪▪▪▪▪▪ONLY BEST AND EXPLAINED ANSWERS WILL BE MARKED AS BRAINLIEST ▪▪▪▪▪▪▪▪▪▪▪▪▪ THOSE WHO DON'T KNOW BE AWAY FROM THIS▪▪▪▪▪▪▪ANSWER IS 6690EXPLAIN HOW??. Created by AmyraSharma890. Math

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October 2021 1 53 Report

☆ONLY FOR MODERATORS OR MATHS GENIUS☆ [tex]find \: the \: sum \: of \: first \: 20 \: terms \: of \: \\ the \: series \\ 2 + 13 + 28 + 47 + 70.......[/tex] ●●●●●●●●●●●●●●●●●●●●● ♡SOLUTION MUST ♡NO SPAMMING ♡CONTENT QUALITY REQUIRED ▪▪▪▪▪▪▪▪▪▪▪▪▪▪ ONLY BEST AND EXPLAINED ANSWERS WILL BE MARKED AS BRAINLIEST ▪▪▪▪▪▪▪▪▪▪▪▪▪

THOSE WHO DON'T KNOW BE AWAY FROM THIS

▪▪▪▪▪▪▪
ANSWER IS 6690
EXPLAIN HOW??

Answers & Comments

MasterYaduvanshi Here,

Series:-2,13,28 47

Now, there CommOn difference

2(difference)13=11

13(diffrrence)28=15

28 (difference)47=19

Again,

Second Difference

11,15,19

15-11=4

19-15=4

then,

Using ....

Quardratic Formula:-

ax²+bx+c

Let to be first term (1)

then,
value=2

a(1)²+b(1)+c

a+b+c=2(a)

When second term (2) then. value=13

Now,

ax²+bx+c=13

a(2)²+b(2)+c=13

4a+2b+c=13 (b)

Again...

when the term (3) value=28

a(3)²+b(3)+c

9a+3b+c=28(c)

Solving Equation a,b,and c

we get,

Value
a=2
b=5

c=-5

Putting the value of ax²+bx+c

Now,

2(x)²+5(x)+(-5)

2x²+5x-5

Here,

Using summation....

2(Summation(x²)+5 x-5

Now,

[ 2 x { (20 x 21 x 41)/6}] + [ 5 x ( 20x21/2)] - (5 x 20)]

(140 x 41) + (50 x 21) - 100= 6690

$\bold{ \huge{thanks}}$

MasterYaduvanshi :-)

AmyraSharma890 now tahnk you

AmyraSharma890 thank*

AmyraSharma890 can u tell me what is summation?? and why you divide 20×21×41 by 6