graph the following quadratic function and find the domain,range,intercepts,axis of symmetry,vertex,and direction of the opening of the parabola.
1.f(x) = x²+4x+4
Domain:
Range:
Axis of symmetry:
Vertex:
intercepts:
Opening:
2.f(x) =2 (x+1)²
Domain:
Range:
Axis of symmetry:
Vertex:
intercepts:
Opening:
palagyan po ng graph
1.f(x) = x²+4x+4
Domain:
Range:
Axis of symmetry:
Vertex:
intercepts:
Opening:
2.f(x) =2 (x+1)²
Domain:
Range:
Axis of symmetry:
Vertex:
intercepts:
Opening:
palagyan po ng graph
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Step-by-step explanation:
f(x)=2(x+1) squared
1.domain=
2.(
3.-1
4. vertex = f(x)=2(x+1) squared
5.-1
6.up