Answer:

Given :  2y + x  < 5

3x - y > 8

To Find : identify at least 3 points that belong to the solution set of the inequalities

Solution:

2y + x  < 5

draw line 2y + x = 5

x = 0  => y   = 5/2

x = 5  => y = 0

draw line

x = 0 , y = 0  => 0 + 0 = 0 < 5

Hence region below line

3x - y > 8

3x - y = 8

x = 0  => y = -8

x = 8/3  , y = 0

draw line

x = 0 , y = 0  => 0 - 0 = 0 > 8 ( not true)

Hence region Right side

Few solutions

( 3, 0) , ( 4 , 0)  , ( 3 , - 1) , (  4, - 1)

Verify

2y + x  < 5          0 + 3 < 5  ,  0 + 4 < 5  ,   -2 + 3 < 5 ,   -2 + 4 < 5

3x - y > 8          9 - 0 > 8  ,  12 - 0 > 8  ,  9 -(-1)  > 8    12 - (-1) > 8

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Step-by-step explanation:

not sure po but k naman