Given: 2y + x < 5

3x -y > 8

To Find identify at least 3 points that belong to the solution set of the inequalities

Solution:

2y + x < 5

draw line 2y + x = 5

x = 0 => y = 5/2

x = 5 => y = 0

draw line

x = 0, y = 0 => 0+0=0<5

Hence region below line

3x - y > 8

3x - y = 8

x = 0 => y = -8

x = 8/3, y = 0

draw line

x = 0, y = 0 => 0-0 =0> 8 (not true)

Hence region Right side

Few solutions

(3, 0), (4,0), (3,-1), (4, -1)

Verify

2y + x < 5 0 + 3 < 5,0 +4<5, -2

+3<5, -2 +4 <5

3x -y > 8 9-0>8, 12-08, 9

-(-1) >8 12- (-1) > 8