graph the equation 4x + 3y = 12 using intercept method. Created by olmempeodj. Math

graph the equation 4x + 3y = 12 using intercept method...

KAntoineDoix

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✒️LINEAR EQUATION

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$\Large\underline{\mathbb{PROBLEM}:}$

Graph the equation 4x + 3y = 12 using intercept method.

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$\Large\underline{\mathbb{ANSWER}:}$

Graph was provided on the given attachment.

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$\Large\underline{\mathbb{SOLUTION}:}$

» In intercept method, we need to find the x- and y- intercept in which the line passes through them.

$\rm (x, \, 0) \: is \: the \: x\text-intercept$
$\rm (0, \, y) \: is \: the \: y\text-intercept$

» Determine the x-intercept when y is zero.

$4x + 3(0) = 12$

$4x = 12$

$\frac{4x}{4} = \frac{12}{4} \\$

$x = 3$

» Therefore, the x-intercept in which the line passes through is (3, 0). Find the y-intercept when x is zero.

$4(0) + 3y = 12$

$3y = 12$

$\frac{3y}{3} = \frac{12}{3} \\$

$y = 4$

» Therefore, the y-intercept in which the line passes through is (0, 4). Now, plot these points on the graph then connect them in the line.

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shy1797 Kantoinedoix pwede po bang pahelp filipino subj lng po thank you po

nealskieron idol

melodyantenor tyy

nealskieron

[Answer]

Solution:

Find the intercepts as follows

let x = 0, in the equation for y-intercept
let y = 0, in the equation for x-intercept

x = 0 → 0 - 3y = 12 → y = -4

← y-intercept

y = 0 → 4x - 0 = 12 → x = 3

← x-intercept

plot the points (0, - 4), (3,0

and draw a straight line through them for graph

[4/3x-4 [10,10,-5 ,5 ]

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✒️LINEAR EQUATION

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