Answer:

Ador and Riza counted 2,835 5-peso coins and 10-peso coins.

Ador counted more number of 10-peso coins than Riza.

Riza counted more number of 5-peso coins than Ador.

Analyzing Word Problem

The word problem above is about the 5-peso coins and 10-peso coins that Ador and Riza counted. There are three questions to answer.

The first question is asking for the total number of 5-peso coins and 10-peso coins that they counted.

The second question is asking for the person who counted more 10-peso coins.

The third question is asking for the person who counted more 5-peso coins.

Question 1: To answer the first question, add all the number of coins that they counted. Make sure to align the numbers correctly.

121

874

525

1 050

+ 386

2,835

Question 2: Compare the numbers of 10-peso coins that they counted.

Ador - 525

Riza - 386

525 is more than 386.

Question 3: Compare the numbers of 5-peso coins that they counted.

Ador - 874

Riza - 1,050

1,050 is more than 874.

Step-by-step explanation:

then you will do this

Let x - ticket for United airlines

7 + x - ticket for American airlines

4 + 2x - ticket for Southwest

x + (7 + x) + (4 + 2x) = 55

4x + 11 = 55

4x = 55 - 11

4x = 44

x = 11 tickets for United airlines

7+x = 18 tickets for American airlines

4+2x = 26 tickets for Southwest airlines

To check, just add all the tickets and u will get 55 tickets.