Good day! Kindly answer all of this, Thank you :) A right triangle has vertices ...

Questions

December 2021 1 31 Report

Good day! Kindly answer all of this, Thank you :)

A right triangle has vertices Q (-1,4), E (2,4), and D (2,-1)
1. Plot the vertices on a coordinate plane and then connect them to form
the triangle.
PS. Follow the picture

2. Find the slope of each side of the triangle.

3. What can you conclude about the perpendicular sides?

PS. I will give the brainiest answer to does who answer all of this question because I need it right away and I will follow you up if you need help :)
-X0TIC

Answers & Comments

HannahPanda

Verified answer

Step-by-step explanation:

Given:

Q (-1,4)

E (2,4)

D (2,-1)

1. Plot the vertices (Refer to the picture)

2. Find the slope

Formula for slope is given by:

$m=\frac{rise}{run}$

$m=\frac{y2-y1}{x2-x1}$

a. Slope of Line QE

Given: Q (-1,4) E (2,4)

$m=\frac{y2-y1}{x2-x1}$

$>Slope is 0<ul><li>b. Slope of Line ED</li></ul><img src=$

$m=\frac{(-1)-(4)}{(2)-(2)}=\frac{-5}{0}$

Slope is undefined

. Slope of Line QD

$m=\frac{y2-y1}{x2-x1}$

$m=\frac{(-1)-(4)}{(2)-(-1)}=\frac{-5}{3}$

Slope is -5/3

3. The perpendicular sides QE and ED have slopes of 0/3 (or 0) and -5/0 respectively. Since the negative reciprocal of -5/0 is 0/5 or 0, I therefore conclude that when two lines are perpendicular, the slope of the first line is the negative reciprocal of the second line.

Note: I'm not sure about the answer in number 3, but since the topic is about slope, I think the question is referring to the relationship between the slope of two perpendicular lines, which is their slopes are the negative reciprocals of each other.

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