Answer:

[tex]\huge\mathfrak{Question}[/tex]

• good boxes of the sizes 12 cm into 10 cm into 12 CM are to be Packed in a cube container for shipment to a drought hit area find the dimensions of the smallest cube container that Aditya can used to pack the food boxes of the given dimensions also find the least number of boxes that can be part in each Cub e container
• good boxes of the sizes 12 cm into 10 cm into 12 CM are to be Packed in a cube container for shipment to a drought hit area find the dimensions of the smallest cube container that Aditya can used to pack the food boxes of the given dimensions also find the least number of boxes that can be part in each Cub e containerifsomeonean swerit correct iwimark themb rain est

[tex]\huge\mathfrak{answer}[/tex]

• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cm
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12))
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12)) =2(120+80+96)
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12)) =2(120+80+96) 2(296)=592 cm
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12)) =2(120+80+96) 2(296)=592 cm 2
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12)) =2(120+80+96) 2(296)=592 cm 2
• Total Surface area of a cuboid is given by T.S.A=2(lb+bh+hl) where l,b,h are dimensions of cuboid.Given l=12 cm,b=10 cm,h=8 cmT.S.A=2((12)(10)+(10)(8)+(8)(12)) =2(120+80+96) 2(296)=592 cm 2 Area of cardboard required to prepare a closed box of given dimensions =592 cm

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