7. The force of gravity on the rock is given by: F = m * g = 3kg * 9.8 m/s^2 = 29.4 N
The change in the rock's momentum is equal to the force of gravity multiplied by the time interval: m = F * t = 29.4 N * 8 s = 235.2 kg*m/s
Therefore, the impulse exerted on the rock by the force of gravity is: J = m = 235.2 kg*m/s
8. The impulse exerted by the group of people acting on the car is equal to the change in the car's momentum: m = 1100 kg * (V_f - V_i) = 2510 kg*m/s - 0 kg*m/s = 2510 kg*m/s
Therefore, the impulse is: J = 2510 kg*m/s + 2510 kg*m/s = 5020 kg*m/s
Explanation:
Note that we assumed that the initial velocity of the car is 0 m/s (i.e., the car was initially at rest when the people started pushing it) and that the final velocity is unknown. The actual value of the impulse will depend on the final velocity of the car.
Answers & Comments
Answer:
7. The force of gravity on the rock is given by: F = m * g = 3kg * 9.8 m/s^2 = 29.4 N
The change in the rock's momentum is equal to the force of gravity multiplied by the time interval: m = F * t = 29.4 N * 8 s = 235.2 kg*m/s
Therefore, the impulse exerted on the rock by the force of gravity is: J = m = 235.2 kg*m/s
8. The impulse exerted by the group of people acting on the car is equal to the change in the car's momentum: m = 1100 kg * (V_f - V_i) = 2510 kg*m/s - 0 kg*m/s = 2510 kg*m/s
Therefore, the impulse is: J = 2510 kg*m/s + 2510 kg*m/s = 5020 kg*m/s
Explanation:
Note that we assumed that the initial velocity of the car is 0 m/s (i.e., the car was initially at rest when the people started pushing it) and that the final velocity is unknown. The actual value of the impulse will depend on the final velocity of the car.