Answer:
please mark as
Explanation:
i don't know
Given tan(A+B)=\sqrt{3}
3
⟹A+B=60∘⋯(1)
tan(A−B)=\sqrt[1]{3}
1
⟹A−B=30∘⋯(2)
(1)+(2)⟹2A=90∘⟹A=45∘
Put A value in (1)
⟹B=60∘−45∘=15∘
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Answers & Comments
Answer:
please mark as
Explanation:
i don't know
Given tan(A+B)=\sqrt{3}
3
⟹A+B=60∘⋯(1)
tan(A−B)=\sqrt[1]{3}
1
3
⟹A−B=30∘⋯(2)
(1)+(2)⟹2A=90∘⟹A=45∘
Put A value in (1)
⟹B=60∘−45∘=15∘