Glucose (C6H1206) is a six-carbon sugar (hexose) which is also known as the blood sugar. It is an energy source that fuels our body. How many percent of carbon is present in glucose? (Complete solution)
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C---6*12=72
H---12*1=12
O---6*16=96
72+12+96=180(add all molar mass equal molecular mass)
% of C = (molar mass of carbon÷molecular mass) * 100%
= (72÷180)*100%
= 0.4*100%
=40%
therefore, 40% Carbon is present in glucose