Given the triangle ABC with vertices A(0,0), B(4,8) and C(6,2). Show that triangle ABC is an isosceles triangle.
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Answer:
Solution given:
A(0,0)
B(4,8)
C(6,2)
we have
distance=
Now
AB=
AC=
BC=
Since
AC=BC
so
∆ABC is an isosceles triangle.