Answer:
Summary: The values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units are y = 3 or - 9.
Explanation:
Solution:
We know that the distance between the two points is given by the Distance Formula = √[( x₂ - x₁ )2 + (y₂ - y₁)2]
By substituting the values of points P (2, - 3) and Q (10, y) in the distance formula, we get
PQ = √(2 - 10)² + (- 3 - y)² = 10
PQ = √(- 8)² + (3 + y)² = 10
Squaring on both sides, we get
64 + (y + 3)2 = 100
(y + 3)2 = 36
y + 3 = √36
y + 3 = ± 6
y + 3 = 6 or y + 3 = - 6
Therefore, y = 3 or - 9 are the possible values for y.
MEET ON KAR
Two resistances when connected in parallel give resultant value of 2 Ω, when connected in series the value becomes 9Ω. Calculate the value of each resistance.
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Answers & Comments
Answer:
Summary: The values of y for which the distance between the points P (2, - 3) and Q (10, y) is 10 units are y = 3 or - 9.
Explanation:
Solution:
We know that the distance between the two points is given by the Distance Formula = √[( x₂ - x₁ )2 + (y₂ - y₁)2]
By substituting the values of points P (2, - 3) and Q (10, y) in the distance formula, we get
PQ = √(2 - 10)² + (- 3 - y)² = 10
PQ = √(- 8)² + (3 + y)² = 10
Squaring on both sides, we get
64 + (y + 3)2 = 100
(y + 3)2 = 36
y + 3 = √36
y + 3 = ± 6
y + 3 = 6 or y + 3 = - 6
Therefore, y = 3 or - 9 are the possible values for y.
Verified answer
MEET ON KAR
Two resistances when connected in parallel give resultant value of 2 Ω, when connected in series the value becomes 9Ω. Calculate the value of each resistance.