Step 1: List the given values.
[tex]\begin{aligned} & V = \text{30.4 L} \\ & n = \text{6.90 mol} \\ & T = 62^{\circ}\text{C} = \text{335.15 K} \end{aligned}[/tex]
Step 2: Solve for the pressure of the gas by using ideal gas equation.
[tex]\begin{aligned} P & = \frac{nRT}{V} \\ & = \frac{(\text{6.90 mol})\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{335.15 K})}{\text{30.4 L}} \\ & = \boxed{\text{6.24 atm}} \end{aligned}[/tex]
Hence, the pressure of the gas is 6.24 atm.
[tex]\\[/tex]
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SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & V = \text{30.4 L} \\ & n = \text{6.90 mol} \\ & T = 62^{\circ}\text{C} = \text{335.15 K} \end{aligned}[/tex]
Step 2: Solve for the pressure of the gas by using ideal gas equation.
[tex]\begin{aligned} P & = \frac{nRT}{V} \\ & = \frac{(\text{6.90 mol})\left(0.082057 \: \dfrac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\right)(\text{335.15 K})}{\text{30.4 L}} \\ & = \boxed{\text{6.24 atm}} \end{aligned}[/tex]
Hence, the pressure of the gas is 6.24 atm.
[tex]\\[/tex]
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