Answer:

It's not possible to have a triangle with a side length that is a complex number, which is the case when `A = √-3`.

However, assuming that `A` is a positive real number, we can proceed to solve for sides `B` and `C`.

Since `B = 60°`, we know that the angle opposite side `A` is `30°` (since the angles in a triangle add up to 180°). Using the sine function, we can find the ratio of side `B` to side `A`:

sin 30° = B / A

Simplifying:

1/2 = B / A

B = (1/2)A

Now we can use the Pythagorean theorem to solve for side `C`:

C² = A² - B²

Substituting `B = (1/2)A`:

C² = A² - (1/2)²A²

Simplifying:

C² = (1 - 1/4)A²

C² = (3/4)A²

C = ± √(3/4)A

Since `A` is positive, we take the positive square root:

C = √(3/4)A = √3A/2

Therefore, if `B = 60°` and `A` is a positive real number, then the sides `B` and `C` are `B = (1/2)A` and `C = √3A/2`.