Step-by-step explanation:
1. ∆ABD and ∆BAC,
AD = BC | Given
AB = BA | Common
∠ DAB = ∠ CBA | Given
∴ ∆ABD ≅ ∆BAC | SAS Rule
2. ∴ ∆ABD ≅ ∆BAC | Proved in (1)
∴ BD = AC | C.P.C.T.
3. ∴ ∆ABD ≅ ∆BAC | Proved in (1)
∴ ∠ ABD = ∠ BAC | C.P.C.T Hence proved
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Step-by-step explanation:
1. ∆ABD and ∆BAC,
AD = BC | Given
AB = BA | Common
∠ DAB = ∠ CBA | Given
∴ ∆ABD ≅ ∆BAC | SAS Rule
2. ∴ ∆ABD ≅ ∆BAC | Proved in (1)
∴ BD = AC | C.P.C.T.
3. ∴ ∆ABD ≅ ∆BAC | Proved in (1)
∴ ∠ ABD = ∠ BAC | C.P.C.T Hence proved