Answer:
Example:
Given: 6/x + x-3/4=2
Step 1: Multiply both sides by the LCM of all denominators. (In the given equaion the LCM is 4x.
(4x) 6x + x-3/4=2 (4x)
24+x^2-3x=8x
Step 2: Write the resulting quadratic equation in standard form
24+x^2-3x-8x=0 ~> x^2-11x+24=0
Step 3:Find the roots of the resulting equation using any methods of solving quadratic equatitons. Let's try using factoring method.
x^2+-11x+24=0 ~> (x-3)(x-8)=0
x-3=0 and x-8=0
[lets put the constant terms to the right side]
x=3 and x=8
Please make me a brainliest
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Answers & Comments
Answer:
Example:
Given: 6/x + x-3/4=2
Step 1: Multiply both sides by the LCM of all denominators. (In the given equaion the LCM is 4x.
(4x) 6x + x-3/4=2 (4x)
24+x^2-3x=8x
Step 2: Write the resulting quadratic equation in standard form
24+x^2-3x-8x=0 ~> x^2-11x+24=0
Step 3:Find the roots of the resulting equation using any methods of solving quadratic equatitons. Let's try using factoring method.
x^2+-11x+24=0 ~> (x-3)(x-8)=0
x-3=0 and x-8=0
[lets put the constant terms to the right side]
x=3 and x=8
Please make me a brainliest